2018 Q88 — Containment Spray TS 3.6.2.1 / LCO 3.0.3

✓ D. Correct. At 08:00 on June 12th, LCO 3.6.2.1 is NOT met (BOTH Trains of Containment Spray are INOPERABLE). LCO 3.6.2.1 does not have any required actions for BOTH Trains of Containment Spray being INOPERABLE. Consequently, the crew must comply with the required actions of LCO 3.0.3. Since ONE Train of Containment Spray is declared OPERABLE at 10:00 on June 12th, the crew no longer has to complete the required actions of LCO 3.0.3. This results in the crew having to comply with the required action of LCO 3.6.2.1 ("With one containment spray system inoperable, restore the inoperable spray system to OPERABLE status within 72 hours or be in at least HOT STANDBY within the next 6 hours"). Consequently, the crew has 72+6 hours from 08:00 on June 12th to place Unit 2 in HOT STANDBY (14:00 on June 15th).

✗ A. 14:00 on June 12th is the date/time if the candidate incorrectly concludes that the required actions of LCO 3.0.3 must be performed. Additionally, the candidate must also incorrectly apply LCO 3.0.3 to require being in HOT STANDBY within 6 hours.

✗ B. 15:00 on June 12th is the date/time if the candidate incorrectly concludes that the required actions of LCO 3.0.3 must be performed (1 hour to initiate actions to place the Unit in a Mode in which the specification does not apply + 6 more hours to be in HOT STANDBY).

✗ C. 08:00 on June 15th is the date/time if the candidate incorrectly interprets the required action of LCO 3.6.2.1 as only allowing 72 hours from 08:00 on June 12th to place Unit 2 in HOT STANDBY.

Ref: Technical Specifications (LCO 3.6.2.1 provided as reference) | LO: NOS05CSPRAY-06 (CONTAINMENT SPRAY SYSTEM) — 10. Given a situation dealing with Containment Spray System operability, examine the situation and apply the appropriate Technical Specification action. | Source: New | Cognitive: Higher